Factor polynomial $$ 3y^{2}-75 $$
Answer
$$ 3y^{2}-75 = 3( y-5 )( y+5 ) $$
Explanation
Step 1 :
After factoring out $ 3 $ we have:
$$ 3y^{2}-75 = 3 ( y^{2}-25 ) $$Step 2 :
Rewrite $ y^{2}-25 $ as:
$$ y^{2}-25 = (y)^2 - (5)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = y $ and $ II = 5 $ , we have:
$$ y^{2}-25 = (y)^2 - (5)^2 = ( y-5 ) ( y+5 ) $$This page was created using
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