Factor polynomial $$ 3x^{3}-7x^{2}+6x-14 $$
Answer
$$ 3x^{3}-7x^{2}+6x-14 = ( x^{2}+2 )( 3x-7 ) $$
Explanation
To factor $ 3x^{3}-7x^{2}+6x-14 $ we can use factoring by grouping:
Group $ \color{blue}{ 3x^{3} }$ with $ \color{blue}{ -7x^{2} }$ and $ \color{red}{ 6x }$ with $ \color{red}{ -14 }$ then factor each group.
$$ \begin{aligned} 3x^{3}-7x^{2}+6x-14 = ( \color{blue}{ 3x^{3}-7x^{2} } ) + ( \color{red}{ 6x-14 }) &= \\ &= \color{blue}{ x^{2}( 3x-7 )} + \color{red}{ 2( 3x-7 ) } = \\ &= (x^{2}+2)(3x-7) \end{aligned} $$This page was created using
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