To factor $ 3x^{3}-6x^{2}+2x-4 $ we can use factoring by grouping:
Group $ \color{blue}{ 3x^{3} }$ with $ \color{blue}{ -6x^{2} }$ and $ \color{red}{ 2x }$ with $ \color{red}{ -4 }$ then factor each group.
$$ \begin{aligned} 3x^{3}-6x^{2}+2x-4 = ( \color{blue}{ 3x^{3}-6x^{2} } ) + ( \color{red}{ 2x-4 }) &= \\ &= \color{blue}{ 3x^{2}( x-2 )} + \color{red}{ 2( x-2 ) } = \\ &= (3x^{2}+2)(x-2) \end{aligned} $$