Factor polynomial $$ 3x^{2}+7x-6 $$

$$ 3x^{2}+7x-6 = ( 3x-2 )( x+3 ) $$

Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:

$$ a = 3 , b = 7 ~ \text{ and } ~ c = -6 $$

Step 2: Multiply the leading coefficient $\color{blue}{ a = 3 }$ by the constant term $\color{blue}{c = -6} $.

$$ a \cdot c = -18 $$

Step 3: Find out two numbers that multiply to $ a \cdot c = -18 $ and add to $ b = 7 $.

Step 4: All pairs of numbers with a product of $ -18 $ are:

PRODUCT = -18
-1     18	1     -18
-2     9	2     -9
-3     6	3     -6

Step 5: Find out which factor pair sums up to $\color{blue}{ b = 7 }$

PRODUCT = -18 and SUM = 7
-1     18	1     -18
-2     9	2     -9
-3     6	3     -6

Step 6: Replace middle term $ 7 x $ with $ 9x-2x $:

$$ 3x^{2}+7x-6 = 3x^{2}+9x-2x-6 $$

Step 7: Apply factoring by grouping. Factor $ 3x $ out of the first two terms and $ -2 $ out of the last two terms.

$$ 3x^{2}+9x-2x-6 = 3x\left(x+3\right) -2\left(x+3\right) = \left(3x-2\right) \left(x+3\right) $$

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