Factor polynomial $$ 3x^{2}-8x+4 $$

$$ 3x^{2}-8x+4 = ( x-2 )( 3x-2 ) $$

Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:

$$ a = 3 , b = -8 ~ \text{ and } ~ c = 4 $$

Step 2: Multiply the leading coefficient $\color{blue}{ a = 3 }$ by the constant term $\color{blue}{c = 4} $.

$$ a \cdot c = 12 $$

Step 3: Find out two numbers that multiply to $ a \cdot c = 12 $ and add to $ b = -8 $.

Step 4: All pairs of numbers with a product of $ 12 $ are:

PRODUCT = 12
1     12	-1     -12
2     6	-2     -6
3     4	-3     -4

Step 5: Find out which factor pair sums up to $\color{blue}{ b = -8 }$

PRODUCT = 12 and SUM = -8
1     12	-1     -12
2     6	-2     -6
3     4	-3     -4

Step 6: Replace middle term $ -8 x $ with $ -2x-6x $:

$$ 3x^{2}-8x+4 = 3x^{2}-2x-6x+4 $$

Step 7: Apply factoring by grouping. Factor $ x $ out of the first two terms and $ -2 $ out of the last two terms.

$$ 3x^{2}-2x-6x+4 = x\left(3x-2\right) -2\left(3x-2\right) = \left(x-2\right) \left(3x-2\right) $$

Polynomial Factoring Calculator