Factor polynomial $$ 3w^{3}-2w^{2}+18w-12 $$
Answer
$$ 3w^{3}-2w^{2}+18w-12 = ( w^{2}+6 )( 3w-2 ) $$
Explanation
To factor $ 3w^{3}-2w^{2}+18w-12 $ we can use factoring by grouping:
Group $ \color{blue}{ 3x^{3} }$ with $ \color{blue}{ -2x^{2} }$ and $ \color{red}{ 18x }$ with $ \color{red}{ -12 }$ then factor each group.
$$ \begin{aligned} 3w^{3}-2w^{2}+18w-12 = ( \color{blue}{ 3x^{3}-2x^{2} } ) + ( \color{red}{ 18x-12 }) &= \\ &= \color{blue}{ x^{2}( 3x-2 )} + \color{red}{ 6( 3x-2 ) } = \\ &= (x^{2}+6)(3x-2) \end{aligned} $$This page was created using
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