Factor polynomial $$ 3tu-3t+10u-10 $$
Answer
$$ 3tu-3t+10u-10 = (3t+10)(u-1) $$
Explanation
To factor $ 3tu-3t+10u-10 $ we can use factoring by grouping.
Group $ \color{blue}{ 3tu }$ with $ \color{blue}{ -3t }$ and $ \color{red}{ 10u }$ with $ \color{red}{ -10 }$ then factor each group.
$$ \begin{aligned} 3tu-3t+10u-10 &= ( \color{blue}{ 3tu-3t } ) + ( \color{red}{ 10u-10 }) = \\ &= \color{blue}{ 3t( u-1 )} + \color{red}{ 10( u-1 ) } = \\ &= (3t+10)(u-1) \end{aligned} $$This page was created using
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