Factor polynomial $$ 3t^{3}-4t^{2}+6t-8 $$
Answer
$$ 3t^{3}-4t^{2}+6t-8 = ( t^{2}+2 )( 3t-4 ) $$
Explanation
To factor $ 3t^{3}-4t^{2}+6t-8 $ we can use factoring by grouping:
Group $ \color{blue}{ 3x^{3} }$ with $ \color{blue}{ -4x^{2} }$ and $ \color{red}{ 6x }$ with $ \color{red}{ -8 }$ then factor each group.
$$ \begin{aligned} 3t^{3}-4t^{2}+6t-8 = ( \color{blue}{ 3x^{3}-4x^{2} } ) + ( \color{red}{ 6x-8 }) &= \\ &= \color{blue}{ x^{2}( 3x-4 )} + \color{red}{ 2( 3x-4 ) } = \\ &= (x^{2}+2)(3x-4) \end{aligned} $$This page was created using
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