It seems that $ 3t^{2}+8t-70 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 3 }$ by the constant term $\color{blue}{c = -70} $.
$$ a \cdot c = -210 $$Step 3: Find out two numbers that multiply to $ a \cdot c = -210 $ and add to $ b = 8 $.
Step 4: All pairs of numbers with a product of $ -210 $ are:
PRODUCT = -210 | |
-1 210 | 1 -210 |
-2 105 | 2 -105 |
-3 70 | 3 -70 |
-5 42 | 5 -42 |
-6 35 | 6 -35 |
-7 30 | 7 -30 |
-10 21 | 10 -21 |
-14 15 | 14 -15 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = 8 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ 8 }$, we conclude the polynomial cannot be factored.