It seems that $ 3t^{2}+8t-55 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 3 }$ by the constant term $\color{blue}{c = -55} $.
$$ a \cdot c = -165 $$Step 3: Find out two numbers that multiply to $ a \cdot c = -165 $ and add to $ b = 8 $.
Step 4: All pairs of numbers with a product of $ -165 $ are:
PRODUCT = -165 | |
-1 165 | 1 -165 |
-3 55 | 3 -55 |
-5 33 | 5 -33 |
-11 15 | 11 -15 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = 8 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ 8 }$, we conclude the polynomial cannot be factored.