Factor polynomial $$ 3j^{3}+5j^{2}+9j+15 $$
Answer
$$ 3j^{3}+5j^{2}+9j+15 = ( j^{2}+3 )( 3j+5 ) $$
Explanation
To factor $ 3j^{3}+5j^{2}+9j+15 $ we can use factoring by grouping:
Group $ \color{blue}{ 3x^{3} }$ with $ \color{blue}{ 5x^{2} }$ and $ \color{red}{ 9x }$ with $ \color{red}{ 15 }$ then factor each group.
$$ \begin{aligned} 3j^{3}+5j^{2}+9j+15 = ( \color{blue}{ 3x^{3}+5x^{2} } ) + ( \color{red}{ 9x+15 }) &= \\ &= \color{blue}{ x^{2}( 3x+5 )} + \color{red}{ 3( 3x+5 ) } = \\ &= (x^{2}+3)(3x+5) \end{aligned} $$This page was created using
Polynomial Factoring Calculator