Factor polynomial $$ 36y^{2}-x^{6} $$
Answer
$$ 36y^{2}-x^{6} = (6y+x^{3})(6y-x^{3}) $$
Explanation
Rewrite $ 36y^2-x^6 $ as:
$$ \color{blue}{ 36y^2-x^6 = (6y)^2 - (x^3)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 6y $ and $ II = x^3 $ , we have:
$$ 36y^2-x^6 = (6y)^2 - (x^3)^2 = ( 6y-x^3 ) ( 6y+x^3 ) $$This page was created using
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