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Factor polynomial $$ 36x^{4}y^{7}z-38y^{3}z^{4} $$
Answer
$$ 36x^{4}y^{7}z-38y^{3}z^{4} = 2y^{3}z(18x^{4}y^{4}-19z^{3}) $$
Explanation
Factor out common factor $ \color{blue}{ 2y^3z } $:
$$ 36x^4y^7z-38y^3z^4 = 2y^3z ( 18x^4y^4-19z^3 ) $$