Rewrite $ 36x^{2}-1 $ as:
$$ 36x^{2}-1 = (6x)^2 - (1)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 6x $ and $ II = 1 $ , we have:
$$ 36x^{2}-1 = (6x)^2 - (1)^2 = ( 6x-1 ) ( 6x+1 ) $$