Factor polynomial $$ -9u^{2}+36 $$
Answer
$$ -9u^{2}+36 = 9( -u+2 )( u+2 ) $$
Explanation
Step 1 :
After factoring out $ 9 $ we have:
$$ -9u^{2}+36 = 9 ( -u^{2}+4 ) $$Step 2 :
Rewrite $ -u^{2}+4 $ as:
$$ -u^{2}+4 = 4 -x^2 = (2)^2 - (u)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 2 $ and $ II = u $ , we have:
$$ -u^{2}+4 = (2)^2 - (u)^2 = ( -u+2 ) ( u+2 ) $$This page was created using
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