Factor polynomial $$ 2y^{3}+3y^{2}+10y+15 $$
Answer
$$ 2y^{3}+3y^{2}+10y+15 = ( y^{2}+5 )( 2y+3 ) $$
Explanation
To factor $ 2y^{3}+3y^{2}+10y+15 $ we can use factoring by grouping:
Group $ \color{blue}{ 2x^{3} }$ with $ \color{blue}{ 3x^{2} }$ and $ \color{red}{ 10x }$ with $ \color{red}{ 15 }$ then factor each group.
$$ \begin{aligned} 2y^{3}+3y^{2}+10y+15 = ( \color{blue}{ 2x^{3}+3x^{2} } ) + ( \color{red}{ 10x+15 }) &= \\ &= \color{blue}{ x^{2}( 2x+3 )} + \color{red}{ 5( 2x+3 ) } = \\ &= (x^{2}+5)(2x+3) \end{aligned} $$This page was created using
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