Factor polynomial $$ 2x^{3}+x^{2}-14x-7 $$
Answer
$$ 2x^{3}+x^{2}-14x-7 = ( x^{2}-7 )( 2x+1 ) $$
Explanation
To factor $ 2x^{3}+x^{2}-14x-7 $ we can use factoring by grouping:
Group $ \color{blue}{ 2x^{3} }$ with $ \color{blue}{ x^{2} }$ and $ \color{red}{ -14x }$ with $ \color{red}{ -7 }$ then factor each group.
$$ \begin{aligned} 2x^{3}+x^{2}-14x-7 = ( \color{blue}{ 2x^{3}+x^{2} } ) + ( \color{red}{ -14x-7 }) &= \\ &= \color{blue}{ x^{2}( 2x+1 )} + \color{red}{ -7( 2x+1 ) } = \\ &= (x^{2}-7)(2x+1) \end{aligned} $$This page was created using
Polynomial Factoring Calculator