Factor polynomial $$ 2x^{3}+7x^{2}-26x-91 $$
Answer
$$ 2x^{3}+7x^{2}-26x-91 = ( x^{2}-13 )( 2x+7 ) $$
Explanation
To factor $ 2x^{3}+7x^{2}-26x-91 $ we can use factoring by grouping:
Group $ \color{blue}{ 2x^{3} }$ with $ \color{blue}{ 7x^{2} }$ and $ \color{red}{ -26x }$ with $ \color{red}{ -91 }$ then factor each group.
$$ \begin{aligned} 2x^{3}+7x^{2}-26x-91 = ( \color{blue}{ 2x^{3}+7x^{2} } ) + ( \color{red}{ -26x-91 }) &= \\ &= \color{blue}{ x^{2}( 2x+7 )} + \color{red}{ -13( 2x+7 ) } = \\ &= (x^{2}-13)(2x+7) \end{aligned} $$This page was created using
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