Factor polynomial $$ 2x^{3}+7x^{2}-16x-56 $$
Answer
$$ 2x^{3}+7x^{2}-16x-56 = ( x^{2}-8 )( 2x+7 ) $$
Explanation
To factor $ 2x^{3}+7x^{2}-16x-56 $ we can use factoring by grouping:
Group $ \color{blue}{ 2x^{3} }$ with $ \color{blue}{ 7x^{2} }$ and $ \color{red}{ -16x }$ with $ \color{red}{ -56 }$ then factor each group.
$$ \begin{aligned} 2x^{3}+7x^{2}-16x-56 = ( \color{blue}{ 2x^{3}+7x^{2} } ) + ( \color{red}{ -16x-56 }) &= \\ &= \color{blue}{ x^{2}( 2x+7 )} + \color{red}{ -8( 2x+7 ) } = \\ &= (x^{2}-8)(2x+7) \end{aligned} $$This page was created using
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