Factor polynomial $$ 2x^{3}+17x^{2}-8x-68 $$

$$ 2x^{3}+17x^{2}-8x-68 = ( x-2 )( x+2 )( 2x+17 ) $$

Step 1 :

To factor $ 2x^{3}+17x^{2}-8x-68 $ we can use factoring by grouping:

Group $ \color{blue}{ 2x^{3} }$ with $ \color{blue}{ 17x^{2} }$ and $ \color{red}{ -8x }$ with $ \color{red}{ -68 }$ then factor each group.

$$ \begin{aligned} 2x^{3}+17x^{2}-8x-68 = ( \color{blue}{ 2x^{3}+17x^{2} } ) + ( \color{red}{ -8x-68 }) &= \\ &= \color{blue}{ x^{2}( 2x+17 )} + \color{red}{ -4( 2x+17 ) } = \\ &= (x^{2}-4)(2x+17) \end{aligned} $$

Step 2 :

Rewrite $ x^{2}-4 $ as:

$$ x^{2}-4 = (x)^2 - (2)^2 $$

Now we can apply the difference of squares formula.

$$ I^2 - II^2 = (I - II)(I + II) $$

After putting $ I = x $ and $ II = 2 $ , we have:

$$ x^{2}-4 = (x)^2 - (2)^2 = ( x-2 ) ( x+2 ) $$

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