To factor $ 2x^{3}-x^{2}-6x+3 $ we can use factoring by grouping:
Group $ \color{blue}{ 2x^{3} }$ with $ \color{blue}{ -x^{2} }$ and $ \color{red}{ -6x }$ with $ \color{red}{ 3 }$ then factor each group.
$$ \begin{aligned} 2x^{3}-x^{2}-6x+3 = ( \color{blue}{ 2x^{3}-x^{2} } ) + ( \color{red}{ -6x+3 }) &= \\ &= \color{blue}{ x^{2}( 2x-1 )} + \color{red}{ -3( 2x-1 ) } = \\ &= (x^{2}-3)(2x-1) \end{aligned} $$