Factor polynomial $$ 2x^{3}-9x^{2}+32x-144 $$
Answer
$$ 2x^{3}-9x^{2}+32x-144 = ( x^{2}+16 )( 2x-9 ) $$
Explanation
To factor $ 2x^{3}-9x^{2}+32x-144 $ we can use factoring by grouping:
Group $ \color{blue}{ 2x^{3} }$ with $ \color{blue}{ -9x^{2} }$ and $ \color{red}{ 32x }$ with $ \color{red}{ -144 }$ then factor each group.
$$ \begin{aligned} 2x^{3}-9x^{2}+32x-144 = ( \color{blue}{ 2x^{3}-9x^{2} } ) + ( \color{red}{ 32x-144 }) &= \\ &= \color{blue}{ x^{2}( 2x-9 )} + \color{red}{ 16( 2x-9 ) } = \\ &= (x^{2}+16)(2x-9) \end{aligned} $$This page was created using
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