Factor polynomial $$ 2x^{3}-9x^{2}+18x-81 $$
Answer
$$ 2x^{3}-9x^{2}+18x-81 = ( x^{2}+9 )( 2x-9 ) $$
Explanation
To factor $ 2x^{3}-9x^{2}+18x-81 $ we can use factoring by grouping:
Group $ \color{blue}{ 2x^{3} }$ with $ \color{blue}{ -9x^{2} }$ and $ \color{red}{ 18x }$ with $ \color{red}{ -81 }$ then factor each group.
$$ \begin{aligned} 2x^{3}-9x^{2}+18x-81 = ( \color{blue}{ 2x^{3}-9x^{2} } ) + ( \color{red}{ 18x-81 }) &= \\ &= \color{blue}{ x^{2}( 2x-9 )} + \color{red}{ 9( 2x-9 ) } = \\ &= (x^{2}+9)(2x-9) \end{aligned} $$This page was created using
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