Factor polynomial $$ 2x^{2}+12x+36 $$

$$ 2x^{2}+12x+36 = 2( x^{2}+6x+18 ) $$

Step 1 :

After factoring out $ 2 $ we have:

$$ 2x^{2}+12x+36 = 2 ( x^{2}+6x+18 ) $$

Step 2 :

Step 2: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:

$$ \color{blue}{ b = 6 } ~ \text{ and } ~ \color{red}{ c = 18 }$$

Now we must discover two numbers that sum up to $ \color{blue}{ 6 } $ and multiply to $ \color{red}{ 18 } $.

Step 3: Find out pairs of numbers with a product of $\color{red}{ c = 18 }$.

PRODUCT = 18
1     18	-1     -18
2     9	-2     -9
3     6	-3     -6

Step 4: Because none of these pairs will give us a sum of $ \color{blue}{ 6 }$, we conclude the polynomial cannot be factored.

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