It seems that $ 2m^{2}+10m+25 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 2 }$ by the constant term $\color{blue}{c = 25} $.
$$ a \cdot c = 50 $$Step 3: Find out two numbers that multiply to $ a \cdot c = 50 $ and add to $ b = 10 $.
Step 4: All pairs of numbers with a product of $ 50 $ are:
PRODUCT = 50 | |
1 50 | -1 -50 |
2 25 | -2 -25 |
5 10 | -5 -10 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = 10 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ 10 }$, we conclude the polynomial cannot be factored.