Factor polynomial $$ 2b^{3}+10b^{2}+3b+15 $$
Answer
$$ 2b^{3}+10b^{2}+3b+15 = ( 2b^{2}+3 )( b+5 ) $$
Explanation
To factor $ 2b^{3}+10b^{2}+3b+15 $ we can use factoring by grouping:
Group $ \color{blue}{ 2x^{3} }$ with $ \color{blue}{ 10x^{2} }$ and $ \color{red}{ 3x }$ with $ \color{red}{ 15 }$ then factor each group.
$$ \begin{aligned} 2b^{3}+10b^{2}+3b+15 = ( \color{blue}{ 2x^{3}+10x^{2} } ) + ( \color{red}{ 3x+15 }) &= \\ &= \color{blue}{ 2x^{2}( x+5 )} + \color{red}{ 3( x+5 ) } = \\ &= (2x^{2}+3)(x+5) \end{aligned} $$This page was created using
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