Factor polynomial $$ 2b^{2}-4ab+2a^{2} $$
Answer
$$ 2b^{2}-4ab+2a^{2} = 2(b-a)(b-a) $$
Explanation
Step 1 :
Factor out common factor $ \color{blue}{ 2 } $:
$$ 2b^2-4ab+2a^2 = 2 ( b^2-2ab+a^2 ) $$Step 2 :
Note that the polynomial $ b^2-2ab+a^2 $ is a perfect square trinomial, so we will use the following formula.
$$ A^2 - 2AB + B^2 = (A - B)^2 $$In this example we have $ \color{blue}{ A = b } $ and $ \color{red}{ B = a } $ so,
$$ b^2-2ab+a^2 = ( \color{blue}{ b } - \color{red}{ a } )^2 $$This page was created using
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