Factor polynomial $$ 28x^{6}y^{3}+20x^{5}y^{4}+4x^{4}y^{2} $$
Answer
$$ 28x^{6}y^{3}+20x^{5}y^{4}+4x^{4}y^{2} = 4x^{4}y^{2}(7x^{2}y+5xy^{2}+1) $$
Explanation
Factor out common factor $ \color{blue}{ 4x^4y^2 } $:
$$ 28x^6y^3+20x^5y^4+4x^4y^2 = 4x^4y^2 ( 7x^2y+5xy^2+1 ) $$This page was created using
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