Factor polynomial $$ 28v^{3}-4v^{2}-35v+5 $$
Answer
$$ 28v^{3}-4v^{2}-35v+5 = ( 4v^{2}-5 )( 7v-1 ) $$
Explanation
To factor $ 28v^{3}-4v^{2}-35v+5 $ we can use factoring by grouping:
Group $ \color{blue}{ 28x^{3} }$ with $ \color{blue}{ -4x^{2} }$ and $ \color{red}{ -35x }$ with $ \color{red}{ 5 }$ then factor each group.
$$ \begin{aligned} 28v^{3}-4v^{2}-35v+5 = ( \color{blue}{ 28x^{3}-4x^{2} } ) + ( \color{red}{ -35x+5 }) &= \\ &= \color{blue}{ 4x^{2}( 7x-1 )} + \color{red}{ -5( 7x-1 ) } = \\ &= (4x^{2}-5)(7x-1) \end{aligned} $$This page was created using
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