Factor polynomial $$ 28a^{2}b-63b $$
Answer
$$ 28a^{2}b-63b = 7b(2a+3)(2a-3) $$
Explanation
Step 1 :
Factor out common factor $ \color{blue}{ 7b } $:
$$ 28a^2b-63b = 7b ( 4a^2-9 ) $$Step 2 :
Rewrite $ 4a^2-9 $ as:
$$ \color{blue}{ 4a^2-9 = (2a)^2 - (3)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 2a $ and $ II = 3 $ , we have:
$$ 4a^2-9 = (2a)^2 - (3)^2 = ( 2a-3 ) ( 2a+3 ) $$This page was created using
Polynomial Factoring Calculator