Factor polynomial $$ 27x^{9}-343y^{6} $$
Answer
$$ 27x^{9}-343y^{6} = (3x^{3}-7y^{2})(9x^{6}+21x^{3}y^{2}+49y^{4}) $$
Explanation
To factor $ 27x^{9}-343y^{6} $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II) (I^2 + I \cdot II + II^2) $$After putting $ I = 3x^3 $ and $ II = 7y^2 $ , we have:
$$ 27x^{9}-343y^{6} = ( 3x^{3}-7y^{2} ) ( 9x^{6}+21x^{3}y^{2}+49y^{4} ) $$This page was created using
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