Factor polynomial $$ 27x^{3}+64y^{3} $$
Answer
$$ 27x^{3}+64y^{3} = (3x+4y)(9x^{2}-12xy+16y^{2}) $$
Explanation
To factor $ 27x^{3}+64y^{3} $ we can use sum of cubes formula:
$$ I^3 + II^3 = (I + II) (I^2 - I \cdot II + II^2)$$After putting $ I = 3x $ and $ II = 4y $ , we have:
$$ 27x^{3}+64y^{3} = ( 3x+4y ) ( 9x^{2}-12xy+16y^{2} ) $$This page was created using
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