Factor polynomial $$ 27s^{3}-125t^{3} $$
Answer
$$ 27s^{3}-125t^{3} = (3s-5t)(9s^{2}+15st+25t^{2}) $$
Explanation
To factor $ 27s^{3}-125t^{3} $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II) (I^2 + I \cdot II + II^2) $$After putting $ I = 3s $ and $ II = 5t $ , we have:
$$ 27s^{3}-125t^{3} = ( 3s-5t ) ( 9s^{2}+15st+25t^{2} ) $$This page was created using
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