Factor polynomial $$ 27b^{3}-64u^{3} $$
Answer
$$ 27b^{3}-64u^{3} = (3b-4u)(9b^{2}+12bu+16u^{2}) $$
Explanation
To factor $ 27b^{3}-64u^{3} $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II) (I^2 + I \cdot II + II^2) $$After putting $ I = 3b $ and $ II = 4u $ , we have:
$$ 27b^{3}-64u^{3} = ( 3b-4u ) ( 9b^{2}+12bu+16u^{2} ) $$This page was created using
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