Factor polynomial $$ 25y^{3}-36y $$
Answer
$$ 25y^{3}-36y = y( 5y-6 )( 5y+6 ) $$
Explanation
Step 1 :
After factoring out $ y $ we have:
$$ 25y^{3}-36y = y ( 25y^{2}-36 ) $$Step 2 :
Rewrite $ 25y^{2}-36 $ as:
$$ 25y^{2}-36 = (5y)^2 - (6)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 5y $ and $ II = 6 $ , we have:
$$ 25y^{2}-36 = (5y)^2 - (6)^2 = ( 5y-6 ) ( 5y+6 ) $$This page was created using
Polynomial Factoring Calculator