Factor polynomial $$ 25x^{6}-49y^{8} $$
Answer
$$ 25x^{6}-49y^{8} = (5x^{3}+7y^{4})(5x^{3}-7y^{4}) $$
Explanation
Rewrite $ 25x^6-49y^8 $ as:
$$ \color{blue}{ 25x^6-49y^8 = (5x^3)^2 - (7y^4)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 5x^3 $ and $ II = 7y^4 $ , we have:
$$ 25x^6-49y^8 = (5x^3)^2 - (7y^4)^2 = ( 5x^3-7y^4 ) ( 5x^3+7y^4 ) $$This page was created using
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