Factor polynomial $$ 225p^{2}-196 $$
Answer
$$ 225p^{2}-196 = ( 15p-14 )( 15p+14 ) $$
Explanation
Rewrite $ 225p^{2}-196 $ as:
$$ 225p^{2}-196 = (15p)^2 - (14)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 15p $ and $ II = 14 $ , we have:
$$ 225p^{2}-196 = (15p)^2 - (14)^2 = ( 15p-14 ) ( 15p+14 ) $$This page was created using
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