Factor polynomial $$ 21a^{4}+14y^{2} $$
Answer
$$ 21a^{4}+14y^{2} = 7(3a^{4}+2y^{2}) $$
Explanation
Factor out common factor $ \color{blue}{ 7 } $:
$$ 21a^4+14y^2 = 7 ( 3a^4+2y^2 ) $$This page was created using
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