Factor polynomial $$ 20x^{4}y^{4}+4x^{3}y^{5}+4x^{2}y^{3} $$
Answer
$$ 20x^{4}y^{4}+4x^{3}y^{5}+4x^{2}y^{3} = 4x^{2}y^{3}(5x^{2}y+xy^{2}+1) $$
Explanation
Factor out common factor $ \color{blue}{ 4x^2y^3 } $:
$$ 20x^4y^4+4x^3y^5+4x^2y^3 = 4x^2y^3 ( 5x^2y+xy^2+1 ) $$This page was created using
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