Factor polynomial $$ 20a^{4}b^{7}c^{3}+24a^{8}b^{9}-16a^{5}bc^{2} $$
Answer
$$ 20a^{4}b^{7}c^{3}+24a^{8}b^{9}-16a^{5}bc^{2} = 4a^{4}b(5b^{6}c^{3}+6a^{4}b^{8}-4ac^{2}) $$
Explanation
Factor out common factor $ \color{blue}{ 4a^4b } $:
$$ 20a^4b^7c^3+24a^8b^9-16a^5bc^2 = 4a^4b ( 5b^6c^3+6a^4b^8-4ac^2 ) $$This page was created using
Polynomial Factoring Calculator