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Factor polynomial $$ 16y^{5}z^{5}-29x^{2}y^{4}z^{3} $$
Answer
$$ 16y^{5}z^{5}-29x^{2}y^{4}z^{3} = y^{4}z^{3}(16yz^{2}-29x^{2}) $$
Explanation
Factor out common factor $ \color{blue}{ y^4z^3 } $:
$$ 16y^5z^5-29x^2y^4z^3 = y^4z^3 ( 16yz^2-29x^2 ) $$