Factor polynomial $$ 8u^{3}+16u^{2}+5u+10 $$
Answer
$$ 8u^{3}+16u^{2}+5u+10 = ( 8u^{2}+5 )( u+2 ) $$
Explanation
To factor $ 8u^{3}+16u^{2}+5u+10 $ we can use factoring by grouping:
Group $ \color{blue}{ 8x^{3} }$ with $ \color{blue}{ 16x^{2} }$ and $ \color{red}{ 5x }$ with $ \color{red}{ 10 }$ then factor each group.
$$ \begin{aligned} 8u^{3}+16u^{2}+5u+10 = ( \color{blue}{ 8x^{3}+16x^{2} } ) + ( \color{red}{ 5x+10 }) &= \\ &= \color{blue}{ 8x^{2}( x+2 )} + \color{red}{ 5( x+2 ) } = \\ &= (8x^{2}+5)(x+2) \end{aligned} $$This page was created using
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