Factor polynomial $$ 16j^{2}-25 $$
Answer
$$ 16j^{2}-25 = ( 4j-5 )( 4j+5 ) $$
Explanation
Rewrite $ 16j^{2}-25 $ as:
$$ 16j^{2}-25 = (4j)^2 - (5)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 4j $ and $ II = 5 $ , we have:
$$ 16j^{2}-25 = (4j)^2 - (5)^2 = ( 4j-5 ) ( 4j+5 ) $$This page was created using
Polynomial Factoring Calculator