It seems that $ 15x^{2}+x+7 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 15 }$ by the constant term $\color{blue}{c = 7} $.
$$ a \cdot c = 105 $$Step 3: Find out two numbers that multiply to $ a \cdot c = 105 $ and add to $ b = 1 $.
Step 4: All pairs of numbers with a product of $ 105 $ are:
PRODUCT = 105 | |
1 105 | -1 -105 |
3 35 | -3 -35 |
5 21 | -5 -21 |
7 15 | -7 -15 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = 1 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ 1 }$, we conclude the polynomial cannot be factored.