Factor polynomial $$ 15x^{2}-23x+4 $$

$$ 15x^{2}-23x+4 = ( 3x-4 )( 5x-1 ) $$

Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:

$$ a = 15 , b = -23 ~ \text{ and } ~ c = 4 $$

Step 2: Multiply the leading coefficient $\color{blue}{ a = 15 }$ by the constant term $\color{blue}{c = 4} $.

$$ a \cdot c = 60 $$

Step 3: Find out two numbers that multiply to $ a \cdot c = 60 $ and add to $ b = -23 $.

Step 4: All pairs of numbers with a product of $ 60 $ are:

PRODUCT = 60
1     60	-1     -60
2     30	-2     -30
3     20	-3     -20
4     15	-4     -15
5     12	-5     -12
6     10	-6     -10

Step 5: Find out which factor pair sums up to $\color{blue}{ b = -23 }$

PRODUCT = 60 and SUM = -23
1     60	-1     -60
2     30	-2     -30
3     20	-3     -20
4     15	-4     -15
5     12	-5     -12
6     10	-6     -10

Step 6: Replace middle term $ -23 x $ with $ -3x-20x $:

$$ 15x^{2}-23x+4 = 15x^{2}-3x-20x+4 $$

Step 7: Apply factoring by grouping. Factor $ 3x $ out of the first two terms and $ -4 $ out of the last two terms.

$$ 15x^{2}-3x-20x+4 = 3x\left(5x-1\right) -4\left(5x-1\right) = \left(3x-4\right) \left(5x-1\right) $$

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