Factor polynomial $$ 14f^{9}+28f^{6}-14f^{5}+14f^{4} $$
Answer
$$ 14f^{9}+28f^{6}-14f^{5}+14f^{4} = 14f^{4}( f^{5}+2f^{2}-f+1 ) $$
Explanation
After factoring out $ 14f^{4} $ we have:
$$ 14f^{9}+28f^{6}-14f^{5}+14f^{4} = 14f^{4} ( f^{5}+2f^{2}-f+1 ) $$This page was created using
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