Factor polynomial $$ 125x^{6}-8 $$
Answer
$$ 125x^{6}-8 = ( 5x^{2}-2 )( 25x^{4}+10x^{2}+4 ) $$
Explanation
To factor $ 125x^{6}-8 $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II)(I^2 + I \cdot II + II^2) $$After putting $ I = 5x^{2} $ and $ II = 2 $ , we have:
$$ 125x^{6}-8 = ( 5x^{2}-2 ) ( 25x^{4}+10x^{2}+4 ) $$This page was created using
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