Factor polynomial $$ 125x^{3}-64y^{3} $$
Answer
$$ 125x^{3}-64y^{3} = (5x-4y)(25x^{2}+20xy+16y^{2}) $$
Explanation
To factor $ 125x^{3}-64y^{3} $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II) (I^2 + I \cdot II + II^2) $$After putting $ I = 5x $ and $ II = 4y $ , we have:
$$ 125x^{3}-64y^{3} = ( 5x-4y ) ( 25x^{2}+20xy+16y^{2} ) $$This page was created using
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