Rewrite $ -4h^{2}+121 $ as:
$$ -4h^{2}+121 = 121 -4x^2 = (11)^2 - (2h)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 11 $ and $ II = 2h $ , we have:
$$ -4h^{2}+121 = (11)^2 - (2h)^2 = ( -2h+11 ) ( 2h+11 ) $$