Rewrite $ -49x^{2}+121 $ as:
$$ -49x^{2}+121 = 121 -49x^2 = (11)^2 - (7x)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 11 $ and $ II = 7x $ , we have:
$$ -49x^{2}+121 = (11)^2 - (7x)^2 = ( -7x+11 ) ( 7x+11 ) $$